self-force on time independent current distribution

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A current distribution \mathbf{J}(\mathbf{r})\, in a magnetic field \mathbf{B}\, experiences a force

\mathbf{F} = \int\!d^3r\, \mathbf{J}\times\mathbf{B}\,.

Supposing that there are no external sources for \mathbf{B}\,, so that it is entirely due to \mathbf{J}\,, then the Biot-Savart law gives

\mathbf{B}(\mathbf{r}) = \frac{\mu_0}{4\pi} \int\!d^3r' \mathbf{J}(\mathbf{r}') \times \frac{ (\mathbf{r}-\mathbf{r}') }{|\mathbf{r}-\mathbf{r}'|^3   }\,.

Thus

\mathbf{F}\, = \int\!d^3r\, \mathbf{J}\times\mathbf{B}\,,
= \frac{\mu_0}{4\pi} \int\!d^3r d^3r'\, \mathbf{J}(\mathbf{r}) \times \left( \mathbf{J}(\mathbf{r}') \times \frac{ (\mathbf{r}-\mathbf{r}') }{|\mathbf{r}-\mathbf{r}'|^3   } \right)\,,
= \frac{\mu_0}{4\pi} \int\!d^3r d^3r'\, \left[
 \mathbf{J}(\mathbf{r}') \left(  \mathbf{J}(\mathbf{r}) \cdot \frac{ (\mathbf{r}-\mathbf{r}') }{|\mathbf{r}-\mathbf{r}'|^3   }  \right)
- \frac{ (\mathbf{r}-\mathbf{r}') }{|\mathbf{r}-\mathbf{r}'|^3 } \left( \mathbf{J}(\mathbf{r}) \cdot \mathbf{J}(\mathbf{r}') \right)

\right]
\,, (BAC-CAB identity)
= \frac{\mu_0}{4\pi} \int\!d^3r d^3r'\, 
 \mathbf{J}(\mathbf{r}') \left(  \mathbf{J}(\mathbf{r}) \cdot \frac{ (\mathbf{r}-\mathbf{r}') }{|\mathbf{r}-\mathbf{r}'|^3   }  \right) \,, (as the integrand is antisymmetric in \mathbf{r}\, and \mathbf{r}'\,)
= -\frac{\mu_0}{8\pi} \int\!d^3r d^3r'\, 
 \mathbf{J}(\mathbf{r}') \left(  \mathbf{J}(\mathbf{r}) \cdot \boldsymbol{\nabla}_{r} \frac{ 1 }{|\mathbf{r}-\mathbf{r}'|^2   }  \right) \,,
= -\frac{\mu_0}{8\pi} \int\!d^3r'\, 
 \mathbf{J}(\mathbf{r}') \int\!d^3r\, \mathbf{J}(\mathbf{r}) \cdot \boldsymbol{\nabla}_{r} \frac{ 1 }{|\mathbf{r}-\mathbf{r}'|^2   } \,,
= \frac{\mu_0}{8\pi} \int\!d^3r'\, 
 \mathbf{J}(\mathbf{r}') \int\!d^3r\, \boldsymbol{\nabla}_r \left(\frac{ \mathbf{J}(\mathbf{r}) }{|\mathbf{r}-\mathbf{r}'|^2 } \right)\,, (since \boldsymbol{\nabla}\cdot\mathbf{J} = 0\, by the continuity equation)
= \frac{\mu_0}{8\pi} \int\!d^3r'\, 
 \mathbf{J}(\mathbf{r}') \int\!dS\, \hat\mathbf{n} \cdot \left(\frac{ \mathbf{J}(\mathbf{r}) }{|\mathbf{r}-\mathbf{r}'|^2 } \right)\,, (by the Divergence theorem)
 = 0\,,

since, by assumption, the region of integration encloses all currents. Thus a static current distribution exerts no net force on itself.

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